so x+2 is under the square root sign so [tex] \sqrt{x+2} [/tex]-2x domain is all possible numbers that will give a real solution (no square root of negative)
so solve for numbers that make the radicand negative x+2 x+2<0 subtract 2 x<-2 so therefor x has to be less than -2 to make the radican negative remember that square root of 0=0 so we can have 0 as inside so domain is all real numbers greater than or equal -2 or [-2, ∞) aka x>-2
