corinam9851 corinam9851

02-04-2019
Chemistry

contestada

How many ml of 0.0500 m cacn2 are needed to make 25.0 ml of 0.0150 m solution? The molar mass of cacn2 is 80.11 g/mol.

Respuesta :

11-04-2019

Answer:

= 7.50 mL

Explanation:

m1v1=m2v2

In this case;

m1=0.05

m2=0.015 and

v2=25.00mL

Therefore;

(.0500M)(v1)=(25.00mL)(.0150M)

V1 = ((25.00mL)(0.0150M))/0.0500 M

= 7.50 mL

Answer Link

Otras preguntas

The _____ language was spoken in Egypt. Latin Egyptian Coptic Meroitic

i need to solve the math problem -2w-6<-10

phil has three times as many rocks has Peter together they have 48 how many more rocks does Phil have then Peter

a bullet train can travel at 170 miles per hour. Will a graph representing distance in miles compared to time in hours show a proportional relationship? explain

What is a reason that these data may be unreliable? It is information that is too old to be considered factual. It was found on the American Cancer Society web

Which sentence is written in second-person point of view? He had never been as scared as he was now. Hyun had never been as scared as he was now. I have nev

Cliff dwellers who disappeared mysteriously

Jarod bought 8 yards of ribbion he needs 209 inches to use to make curtains how many inched of ribbon does he have.

How did The Renaissance pave the way for the Scientific Revolution

Which purpose of mythology is illustrated by the myth of Arachne? the Initiation history the Quest religion