neharani neharani

03-01-2017
Mathematics

contestada

how many real solution does the equation x^7+14x^5+16x^3+30x-560=0

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bhatiakartik10 bhatiakartik10

03-01-2017

Consider the given equation to be f(x) whose first derivative is positive for all real x. This implies f(x) is a strictly increasing function. Thus it has only 1 root.

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15^7-15^4is equal to O 15^3 O 15 ^11 0 1 O15 7/4