benudumi2468
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02-03-2022
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02-03-2022
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x^2+y^2≤ 4y, x^2+y^2≤4x
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[tex] \frac{5}{5 \sqrt{6 + 2 \sqrt{3} } } \times ( \frac{1}{5 \sqrt{3} } + \frac{3 \sqrt{2} }{2 \sqrt{3} } - \frac{2 \sqrt{3} }{3 \sqrt{2} } ) = [/tex] ..
